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30. You need the random python module which is part of your standard library. Use the code... from random import randint. num1= randint(0,9) This will set the variable num1 to a random number between 0 and 9 inclusive. answered Apr 1, 2021 at 10:09. SamTheProgrammer.
import random num = random.randrange(1, 10**3) # using format num_with_zeros = '{:03}'.format(num) # using string's zfill num_with_zeros = str(num).zfill(3) Alternatively if you don't want to save the random number as an int you can just do it as a oneliner: '{:03}'.format(random.randrange(1, 10**3)) python 3.6+ only oneliner:
78. The only differences between randrange and randint that I know of are that with randrange([start], stop[, step]) you can pass a step argument and random.randrange(0, 1) will not consider the last item, while randint(0, 1) returns a choice inclusive of the last item. So, I don't understand why randrange(0, 1) doesn't return 0 or 1.
I am assuming that 16 is a argument to the built in function int that tells python that the given string is in base 16 (hexadecial). – Charlie Parker Commented Jul 3, 2016 at 21:05
I know how to generate a random number within a range in Python. random.randint(numLow, numHigh) And I know I can put this in a loop to generate n amount of these numbers. for x in range (0, n): listOfNumbers.append(random.randint(numLow, numHigh)) However, I need to make sure each number in that list is unique.
random.random() Return the next random floating point number in the range [0.0, 1.0). But if your inclusion of the numpy tag is intentional, you can generate many random floats in that range with one call using a np.random function.
The fastest way to generate random numbers if you're going to be doing lots of them is by using numpy: In [1]: import numpy as np In [2]: import random In [3]: %timeit [random.choice([-1,1]) for i in range(100000)] 10 loops, best of 3: 88.9 ms per loop In [4]: %timeit [(-1)**random.randrange(2) for i in range(100000)] 10 loops, best of 3: 110 ms per loop In [5]: %timeit [1 if random.random ...
To avoid wasting time looping for useful random number, I suggest you create a list from 0 to 9 using for loop [0,1,....9,]. then you shuffle this list once randomly. [ 4,8,0,....1] to get a random number, just "poll" the first number from this list each time you want a random number (which will not exist in the list the next time read).
random.seed(a, version) in python is used to initialize the pseudo-random number generator (PRNG). PRNG is algorithm that generates sequence of numbers approximating the properties of random numbers. These random numbers can be reproduced using the seed value. So, if you provide seed value, PRNG starts from an arbitrary starting state using a seed.
4. There are many interesting ways to generate randomness without resorting to random (or numpy). For instance, you can use the built in hash function: def rand_generator(seed, N=10**6, a=0, b=10, integer = True): '''For a given seed, this function returns N pseudo-random between a and b'''. rands =[]